Physics, asked by shivani654jat, 5 months ago

please answer fast...
calculat the torque on a 20 turns square coil of side 5 cm carrying a current of 10 A when placed making an angle of 300 with the magnetic field of 0.8T

Answers

Answered by amoghnasa

1

Explanation:

torque = MBsin$

torque = NAi *Bsin$ = 20*(0.05)²*10*0.8*sin30°

= 20*1/2*8*0.0025

= 0.2 N/m

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