Math, asked by sakshikashyap450, 6 months ago

please answer fast
class 10 math's questions​

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Answered by kudratkomolafehassan
1

is sinA = 3/5

sinA=3(opp)/5(hyp)

so Adj²=5²-3²

Adj²=25-9=16

Adj=√16 = 4

therefore tanA=opp/adj

tanA=3/4

therefore cosA=adj/hyp

cosA=4/5

therefore cosecA=1/sinA

cosecA=1/(3/5)= 5/3

therefore secA=1/cosA

secA=1/(4/5) = 5/4

therefore cotA=1/tanA

cotA=1/(3/4) = 4/3

I hope this helps

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