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class 10 math's questions
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is sinA = 3/5
sinA=3(opp)/5(hyp)
so Adj²=5²-3²
Adj²=25-9=16
Adj=√16 = 4
therefore tanA=opp/adj
tanA=3/4
therefore cosA=adj/hyp
cosA=4/5
therefore cosecA=1/sinA
cosecA=1/(3/5)= 5/3
therefore secA=1/cosA
secA=1/(4/5) = 5/4
therefore cotA=1/tanA
cotA=1/(3/4) = 4/3
I hope this helps
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