Math, asked by nehanoeli, 5 months ago

please answer fast

Consider the arithmetic sequence 1,8,15,22.......

a) what is the common difference?

b) What will be the remainder when the terms are
divided by its common
difference ?

c) which is the first there digit term of this sequence?

d) with write the algebraic form of this sequence

e) How many terms are there below 100 in this sequence?​

Answers

Answered by ravi2303kumar
1

Answer:

a) 7

b) the remainder will be the previous term

c) 16th term

d) tₙ = 7n-6

e) 15 terms

Step-by-step explanation:

a) 8-1 = 7

b) the remainder will be the previous term

c)

a=1, d = 7,

tₙ >99

a+(n-1)d >99

1 + (n-1)7>99

1+7n-7 > 99

7n > 99+6

7n > 105

n > 105/7

n > 15

16th term is the first 3 digit term

d) tₙ = a + (n-1)d

   tₙ = 1+(n-1)(7)

  tₙ = 1+7n-7

  tₙ = 7n-6

6) from question c, it is obvious that there are 15 terms below 100

Similar questions