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Answered by
2
Answer:
1)
Step-by-step explanation:
1) 1+8x³
=8x³+1
= (2x)³+1³
= (2x + 1)(4x²-2x+1)
2) 3x³-x²-3x+1
=3x³-3x-x²+1
=3x(x-1) +x(x-1)
= (3x+x)(x-1)
Answered by
1
Answer:
(i)(1+2x) and(1-2x+4x^2)
(ii)(x + 1) , (x - 1) , (3x - 1)
Step-by-step explanation:
(i) 1 + 8x³
can be written as
1^3+2x^3 {using the identity a^3+b^3=(a+b)(a^2-ab+b^2)}
where,
a=1 , b=2x
so by equating we get,
(1+2x)(1-2x+4x^2)=1+8x^3
Hence the factors of it are,
(1+2x) and(1-2x+4x^2)
(ii) 3x³ - x² - 3x + 1
see attachment for this answer.
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