Please answer fast. Don't write wrong anwer for points
Attachments:
Answers
Answered by
0
Answered by
1
Answer:
Step-by-step explanation:
it is option d
We know that, odd intergers are 1,3,5,...
So, it can be written in the form of 2m + 1.
where, m = integer = z
or m = ...,-1,0,1,2,3,...
∴ 2m + 1 = ...,-3,-1,1,3,5,...
Alternate method
Let 'a' be the given positive integer .On dividing 'a' by 2, let m be the quotient and r be the remainder. Then, by Euclid's division algorithm, we have
a = 2m + r, where 0 ≤ r < 2
⇒ a = 2m + r, where r = 0 or r = 1
⇒ a = 2m or 2m + 1
when a = 2m + 1 for some integer m, then clearly a is odd.
Similar questions