Math, asked by sancho27, 5 months ago

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Answered by spoorthinbhat48
0

Answer:

using the identity 1 + tan² theta = sec² theta

sin² theta+ cos² theta = 1

1- sin² theta = cos² theta

(a+b)(a-b) = a²-b²

sec² theta = 1/ cos² theta

we get

(sec² theta)(cos² theta)

(1/ cos² theta)( cos² theta)= 1

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