Question

please answer fast friends...

Answer 1

αяєα σf тяαρєzιυм =

$24.5cm ^{2}$

$\frac{1}{2} \times (ad + bc) \times ab = 24.5 \\ \frac{1}{2} (10 + 4) \times ab = 24.5 \\ ab = 3.5cm$

αяєα σf qυα∂яαит=

$\frac{1}{4} \pi \: r^{2}$

$0.25 \times \frac{22}{7} \times 3.5 \times 3.5 \\ = 9.625cm ^{2}$

αяєα σf ѕнα∂є∂ яєgισи=

$24.5 - 9.625 \\ = 14.875cm^{2}$

Answer 2

Answer:

Step-by-step explanation:area of trapezium ABCD= 1\2x(sum of parallel sides)X height

=1\2x(10+4)xCE=24.5cm²

=1\2x14xCE=24.5

CE=24.5x2\14

CE=3.5cm

Radius of circle=3.5cm

Area of the circle in the figure=πr²\4

=22\7x3.5x3.5\4

=38.5\4

=9.625cm²

Area of shaded region=24.5-9.625

=14.875cm².ANS