Question

please answer fast guys................

Answer 1

40%

Mass of oxygen= 16 u

Mass of sulphur=32 u

Total mass=(32*1) + (16*3)

=32+48

=80

Mass percentage of sulphur

=(32/80)*100

=0.4*100

=40%

Answer 2

Answer:

D) 40 •/•

Explanation:

SO3

atomic mass of Oxygen = 16u

there are 3 oxygen atom then total mass of oxygen is 3×16u = 48u

atomic mass of sulphur is given 32u

then total mass of molecule is 32 + 48 = 80u

mass percentage of sulphur = (mass of sulphur)×100/(total mass of molecule)

= 32×100/80

= 40 •/•