Question

please, answer fast guys, its urgent....

Answer 1

mass of the bullet (m) = 10 g = (10/1000) kg =0.01 kg
Initial velocity (u) = 150 m/s
Final velocity (v) = 0 m/s
Time taken (t) = 0.03 sec

i. Calculation of the distance of penetrationof the bullet into the block:  

Calculation of the distance of penetrationof the bullet into the block = Displacement

Displacement = average velocity × time
Displacement = [(u + v) / 2] × time
Displacement = [(150 + 0) / 2] × 0.03
Displacement = 2.25 m


ii. Calculation of the magnitude of the force exerted by the wooden block on the bullet:
the magnitude of the force exerted by the wooden block on the bullet = Retarding force
Retarding force = mass × reatardation
Retarding force = mass ×[ (Intitial velocity - Final velocity) / t ]
Retarding force = 0.01 ×[ (150 - 0) / 0.03 ] N
Retarding force = [150/3] N
Retarding force = 50 N

Answer 2

Please refer to the attachment for your answer.

Your answers will be -

$\boxed{(1) 2.25 m}$

$\boxed{(2) 50 N}$

$\red{Hope\: it'll\: help}$