Question

please answer fast I'll mark you brainliest​

Answer 1

Answer:

2(Sin 2 theta +cos 2 theta )=2

Answer 2

EXPLANATION

Equation =

let theta = A

=> (sinA + cosA) ^2 + (sinA - cosA ) ^2

=> ( sin^2A + cos^2A + 2sinAcosA ) +

(sin^2A + cos^2A - 2 sinAcosA)

=> (1 + 2sinAcosA) + (1 - 2sinAcosA)

1 + 1 = 2

FORMULA USED.

$(a \: + b) {}^{2} = {a}^{2} + {b}^{2} + 2ab$

$(a - b) {}^{2} = {a}^{2} + {b}^{2} - 2ab$

SOME OTHER FORMULA

$( {a}^{2} - {b}^{2} ) = (a \: + b)(a \: - b)$

=> (a^2 + b^2 ) = (a + b)^2 - 2ab

=> (a^2 - b^2 ) = (a - b)^2 + 2ab