Physics, asked by hhhhschooleww, 2 months ago

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Answered by vipinkumar212003
1

Explanation:

R_1=R_2=R_3=R_4=4 \: Ω \\ \blue{\underline{connecting \: R_1 \: and \: R_4 \: in \: parallel}:} \\  \frac{1}{R_P}  =  \frac{1}{R_1}  +  \frac{1}{R_4}  \\  =  \frac{1}{4}  +  \frac{1}{4}  \\  =  \frac{2}{4} =  \frac{1}{2}   \\  R_{P1} = 2 \: Ω\\ \blue{\underline{connecting \: R_2 \: and \: R_3 \: in \: parallel}:} \\ similrly, \:  \: R_{P2} = 2 \: Ω \\ \blue{\underline{connecting \: R_{P1} \: and \: R_{P2} \: in \: series}:} \\ R_{equivalent} = R_{P1}  +   R_{P2} \\  = 2 \: Ω + 2 \: Ω \\  = 4\: Ω \\  \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \green{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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