Question

please answer fast ...

I will mark as brain liest answer

and will also follow you abd

thank you .......​

Answer 1

AnsWer :

C ) b = - c.

Solution :

We have, Polynomial.

$\tt \dagger \: \: \: \: \: p(x) = a{x}^{2} + bx + c$

Condition.

• Sum of zeros and product of zeros be equal.

$\blacksquare \: \tt Sum \: of \: Zeros . \\ \tt\alpha + \beta = \dfrac{ - b}{a} = \dfrac{coefficient \: x}{coefficient \: {x}^{2} }$

$\blacksquare \: \tt product \: of \: Zeros . \\ \tt\alpha \beta = \dfrac{ c}{a} = \dfrac{constant \: term}{coefficient \: {x}^{2} }$

A/Q,

$\tt \longmapsto \dfrac{ - b}{ \cancel a} = \dfrac{c}{ \cancel a}$

$\tt \longmapsto - b=c.$

Or, We can also Write as,

$\tt \longmapsto b= - c.$

Therefore, Option C) is right answer of this question.