Question

Please answer fast ...I will mark as brainliest​

Answer 1

Answer:

Step-by-step explanation:

Consider AB and CD are two parallel tangents to the circle.

Consider P and Q be the point of intersection of tangents at circle and POQ be a line segment.

Construction: Join OP and OQ where O is the centre of a circle.

Proof: OQ ⊥CD and OP ⊥ AB.

Since AB || CD, OP || OQ.

As OP and OQ pass through O,

Hence, POQ is a straight line which passes through the centre of a circle.

I hope this answer would help you. Good luck.