Question

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Answer 1

ᴛʜᴇ ᴅᴀᴛᴀ ᴀʙᴏᴠᴇ ᴄᴀɴ ʙᴇ ʀᴇᴩʀᴇꜱᴇɴᴛᴇᴅ ᴜꜱɪɴɢ ʙᴀʀ ɢʀᴀᴩʜ ʀᴇᴩʀᴇꜱᴇɴᴛᴀᴛɪᴏɴ .

ʀᴇꜰᴇʀ ᴛᴏ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ ʙᴇʟᴏᴡ ꜰᴏʀ ᴅᴇᴛᴀɪʟꜱ !

Answer 2

3 values possible

By relative speed

First meeting time D/6-b or D/b-6

Second meeting at starting point

So time of second meeting will be

LCM (D/6,D/b)=D/hcf(6,b)

So now when b is less than 6

no of meeting=D/hcf(6,b) ×(6-b)/D=2.(1)

And

When b is more than 6

No of meeting=D/hcf(6,b)×(b-6)/D=2..(2)

Now by hit nd trial

Put the values of b from 1 to 30 which satisfies the condition of equation 1 and 2