Math, asked by rapunzel3156, 1 year ago

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Answered by Shiven01
1

Answer:

(I) area of BCD = 1/2bh=1/2*10*16=80cm²

area of BAD=1/2bh=1/2*6*16=48cm²

area of quadrilateral= 80+48= 128cm²

(ii) area of ABC=1/2bh=1/2*6*8=24cm²

area of ADC= 1/2bh=1/2*3*8= 12cm²

area of quadrilateral = 24+12=36cm²

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