Question

please answer fast.......if the tangent to the parabola y^2= 4ax at (x1,y1) and (x2,y2) meet on the axis then?????
answer is x1=x2
please give solution.............

Answer 1

If the tangents and the normals at the extremities of a focal chord intersect at (x1,y1) and (x2,y2) respectively then:

a) x1=x2

b) x1=y2

c) y1=y2

d) x2=y1

Also explain your answer...

5 years ago

Answers : (1)

Ans:

if the parabola is Y2= 4ax

take the focal chord which is easy for calculation e.x. LR (latus rectum)

then coordinates of extremities would be (a,2a) and (a,-2a)

equation of tangent of parabola at (a,2a) :

T=0 : 2ay = 2a(x+a)

y = x+a................................. (1)

equation of tangent of parabola at (a,-2a) :

T=0 -2ay = 2a (x+a)

y = -x-a .........................(2)

point of intersection of both tangents is (X1, Y1)

after solving eq1 and eq2 X1 = -a and Y1 = 0

so ( -a, 0)

eqn of normal of parabola at (a, 2a)

y = -x +3a ...............................(3)

eqn of normal of parabola at (a, -2a)

y = x -3a..............................(4)

so point of intersection of normal's : (X2, Y2)

after solving eq3 and eq4 X2= 3a and Y2 = 0

so we conclude... for y2= 4ax

Y1= Y2

similarly if u take Y2= -4aX then also you will get the same result..

in case of X2= 4aY and X2= -4 aY

you wil get X1 = X2

Thanks and Regards,