Math, asked by EnchantedBoy, 9 months ago

please answer fast if you know then only answer with full process please​

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Answered by mnandhini335
3

Answer:

1)a=k+2,a2=4k-6,a3=3k+2

a2-a=a3-a2

4k-6-(k+2)=3k+2-(4k-6)

4k-6-k-2=3k+2-4k+6

3k-8=8-k

3k+k=8+8

4k=16

k=16/4

k=4

the value of k=4

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2)a=15,a2=12,a3=9

d=12-15

= -3

an=a+(n-1)d

=15+(n-1)-3

=15-3n+3

=18-3n

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3)a=4,a2=9,a3=14

d=9-4=5

an=139

an=a+(n-1)d

139=4+(n-1)5

139=4+5n-5

139= -1+5n

139+1=5n

140=5n

140/5=n

28=n

I hope you understand

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Answered by cutiemoksha
2

Answer:

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