Question

please Answer fast important question​

Answer 1

Answer:

1. a) using the rationalization

2root3 +3root2 divided by 2root3 -3root2 ×2root3 +3root2 divided by 2root3 +3root2

therefore (a+b)(a-b)=a²-b²

(2root3)²-(3root2)²=12-18=-6

(2root3)(2root3)+(2root3)3root2)+(3root2)(2root3)+(3root2)(3root2)=(12)+(6root6)+(6root6)+(18)=(30+12root6)÷-6

taking 6 common from 30 and 12root6

=[6(5+2root6)]÷-6= -5-2root6

a= -5 and b= -2