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In a cricket match a batsman hits 6 four times from 52 balls . Find the probability that he
a) hits 6
b)does not hit 6
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3
Answer:
1) 1/13
2) 0.92
Step-by-step explanation:
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A batsman hits 6 = 4 times
Total balls =52
(I) Probability of hits 6 = hits 6/ total outcomes
=4/52=1/13
(II) probability of does not hit six =(52-4)/52
=48/52=12/13
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Total balls =52
(I) Probability of hits 6 = hits 6/ total outcomes
=4/52=1/13
(II) probability of does not hit six =(52-4)/52
=48/52=12/13
Hopefully it’s helpful for you
Please mark me as a brainliest
Thanks
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