Math, asked by atiksh1405, 9 months ago

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In a cricket match a batsman hits 6 four times from 52 balls . Find the probability that he
a) hits 6
b)does not hit 6

Answers

Answered by AshMaXSiRa
3

Answer:

1) 1/13

2) 0.92

Step-by-step explanation:

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Answered by nitinsengar3
9
A batsman hits 6 = 4 times
Total balls =52
(I) Probability of hits 6 = hits 6/ total outcomes
=4/52=1/13
(II) probability of does not hit six =(52-4)/52
=48/52=12/13

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