Question

Please answer fast in copy ​

Answer 1

Given :

•P = 2y² - 5 - 2y

•Q = y² - 3y + 6

•R = y² - 4y + 2

To Find :

• P + 2Q + 2R

Solution :

→ P + 2Q + 2R

Put the value of P,Q and T

$\longrightarrow \sf \: (2 {y}^{2} - 5 - 2y) + 2( {y}^{2} - 3y + 6) + 2( {y}^{2} - 4y + 2)$

$\longrightarrow \sf \:( 2 {y}^{2} - 5 - 2y )+ (2 {y}^{2} - 6y + 12) + (2 {y}^{2} - 8y + 4)$

$\longrightarrow \sf \:2 {y}^{2} - 5 - 2y + 2 {y}^{2} - 6y + 12 + 2 {y}^{2} - 8y + 4$

$\longrightarrow \sf \:2 {y}^{2} + 2 {y}^{2} + 2 {y}^{2} - 2y - 6y - 8y - 5 + 12 + 4$

$\longrightarrow \sf \: 6 {y}^{2} - 8y - 8y - 5 + 16$

$\longrightarrow \: \sf \red{ 6 {y}^{2} - 16y + 11}$

$\therefore$ Value of P + 2Q + 2R = 6y² - 16y + 11