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Answered by ravi2303kumar
3

Answer:

The height of the tree = 22.8m

Step-by-step explanation:

given, the height of the pole = 3.8 m

length of the shadow of pole = 1.3m

imagine these measures as the opposite and adjacent sides resply,

then the angle of inclination (taken θ) is given by,

  tanθ = \frac{opp}{a dj} = \frac{3.8}{1.3}

  => θ = tan⁻¹(\frac{3.8}{1.3})

having this angle of inclination value as the same in the second case,

we have the length of shadow of tree as the adjacent side of the second imaginary triangle.

so, we have to calculate the opposite side of the triangle (take it as h ) , which actually will be the height of the tree.

ie., we have tan(tan⁻¹(\frac{3.8}{1.3})) = \frac{opp_2}{a dj_2} = \frac{h}{7.8}

=> \frac{3.8}{1.3} = \frac{h}{7.8}

=> h = \frac{3.8}{1.3} * (7.8)

       = 3.8*6

       = 22.8 m

ie., the height of the tree = 22.8m

Answered by akbaruddinmultani
3

Answer:

yes true

btw

how was your exam

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