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let x/y be the original fraction
x = numerator
y = denominator
the numerator of a fraction is 6 less than the denominator
x = y - 6
if 3 is added to the numerator, the fraction is equal to 2/3
(x + 3)/y = 2/3 cross multiply
3(x + 3) = 2y
by solving the system of equations
x = y - 6
3(x + 3) = 2y
we find
x = 3
y = 9
the original fraction is 3/9.
x = numerator
y = denominator
the numerator of a fraction is 6 less than the denominator
x = y - 6
if 3 is added to the numerator, the fraction is equal to 2/3
(x + 3)/y = 2/3 cross multiply
3(x + 3) = 2y
by solving the system of equations
x = y - 6
3(x + 3) = 2y
we find
x = 3
y = 9
the original fraction is 3/9.
Coolamangolu:
Let x= numerator and y= denominator
Answered by
1
HOPE YOU UNDERSTAND !!!!
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