Question

PLEASE ANSWER FAST IT'S TOO URGENT​

Answer 1

Answer:

a = 8, b = 5

Step-by-step explanation:

For a system of linear equations

$a_{1} x + b_{1} y + c_{1} = 0\\a_{2} x + b_{2} y + c_{2} = 0$

to have infinitely many solutions, we should have

$\frac{a_{1} }{a_{2} } =\frac{b_{1} }{b_{2}} =\frac{c_{1} }{c_{2} }$

Here,

$\frac{3}{5} = \frac{-(a+1)}{1-2a} = \frac{2b-1}{3b}$

Now we will cross-multiply and equate.

3 - 6a = -5a - 5 ⇒ 11a = 8 ⇒ a = 8

9b = 10b - 5 ⇒ b = 5