Question

please answer fast it's urgent​

Answer 1

Given:-

▫ ky² - 9y + 1 = 0

Find:-

▫ Value of k

Solution:-

we, know that

$\huge{\underline{\boxed{\sf{b}^{2} - 4ac = 0}}}$

where,

• a = k
• b = -9
• c = 1

So,

$\mapsto\sf{b}^{2} - 4ac = 0$

$\mapsto\sf{(- 9)}^{2} - 4(k)(1) = 0$

$\mapsto\sf81 - 4k(1) = 0$

$\mapsto\sf81 - 4k = 0$

$\mapsto\sf - 4k = - 81$

$\mapsto\sf k = \dfrac{- 81}{ - 4}$

$\mapsto\sf k = \dfrac{81}{4}$

Hence, if k = 81/4 then, the given eq. becomes a perfect square