Question

please answer fast its important ​

Answer 1

Given, force of engine = 40000 N

Force of friction = 5000 N

Mass of engine = 8000 kg

Total weight of wagons = 5 x 2000 kg = 10000 kg

(a) The net accelerating force 

= Force exerted by engine – Force of fricition

= 40000 N – 5000 N = 35000 N

(b) The acceleration of the train

We know that, F = mass x acceleration

Or, 35000 N = (mass of engine + mass of 5 wagons) X a

Or, 35000N=(8000kg+10000kg)×a35000N=(8000kg+10000kg)×a

Or, 35000N=18000kg×a35000N=18000kg×a

⇒a=35000N18000 kg=1.944ms−2⇒a=35000N18000 kg=1.944ms-2

(c) The force of wagon 1 on wagon 2 = mass of four wagons x acceleration

⇒F=4×2000 kg×1.944ms−2⇒F=4×2000 kg×1.944ms-2

⇒F=8000 kg×1.944ms−2⇒F=8000 kg×1.944ms-2

⇒F=1552N⇒F=1552N

Thus, (a) The net accelerating force = 35000N

(b) The acceleration of train = 1.944 ms–2

(c) The force of wagon 1 on 2 = 1552 N