Please answer fast its my exam 4 ,9,10,11 questions
Attachments:
Answers
Answered by
0
*solve question 4 by formula
2πrh=704
*9) Surface area of cube=
2(lb+BH+HL)
but there are three sides that paper covering
hence
area covered by paper= lb+bh+hl
*10) both have same height
one is right cylinder and another is cube
cylinder have diameter but cube don't have.
cylinder is round cross section but cube is rectangular cross section
find area by
cylinder= 2πrh= 2*22/7*3*6= 113.14
area of cube= 6a^2 = 6*6^2= 2160
cube has larger lateral surface area
2πrh=704
*9) Surface area of cube=
2(lb+BH+HL)
but there are three sides that paper covering
hence
area covered by paper= lb+bh+hl
*10) both have same height
one is right cylinder and another is cube
cylinder have diameter but cube don't have.
cylinder is round cross section but cube is rectangular cross section
find area by
cylinder= 2πrh= 2*22/7*3*6= 113.14
area of cube= 6a^2 = 6*6^2= 2160
cube has larger lateral surface area
Rudrankshi:
can you please solve 9 th question
yes
area covered by paper= lb+bh+hl
given l= 80, b=30, h=40
hence area = 80*30+30*40+40*80
=6800 sa.cm
6800 sq.cm
Answered by
0
Please post clear images.
Similar questions