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it can be solved by the midpoint theorem
yogeswari2002:
Ik tht..but how??
in triangle ADB, S anti are midpoints of a d and a b respectively therefore by the midpoint theorem ft equals to half of DB similarly GH equals to half of DB therefore GH equal to ft similarly H E equal to half of a c and F G equal to half of AC therefore f g = h e so we conclude that FE parallel GH and s e = g h also FG parallel e h and f g = e h so e f g h is a rectangle because opposite sides are equal and the angle of intersection of these two lines are 90 degrees
therefore part 1 angle is equal to 90 degrees
and part 2 G and H are midpoints of BC and BD
Thank u so much
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