Question

Please answer fast .............................
Maths........................
The perimeter of a sector of a circle of radius 5.6 cm is 27.2 cm. Its area is

Answer 1

Given that perimeter of a sector = 27.2cm.

Given that Radius of the circle r = 5.6cm.

$W.K.T, perimeter of the sector of circle = 2r + 2pir * \frac{theta}{360}$

$27.2 = 2r(1 + pi * \frac{theta}{360} )$

$27.2 = 2 * 5.6(1 + pi * \frac{theta}{360} )$

$27.2 = 11.2(1 + pi * \frac{theta}{360} )$

$\frac{27.2}{11.2} = 1 + pi * \frac{theta}{360}$

$2.43 = 1 + pi * \frac{theta}{360}$

$2.43 - 1 = pi * \frac{theta}{360}$

$1.43 = pi * \frac{theta}{360}$


Now,

We know that Area of sector in degrees = 

$\frac{theta}{360} * \pi r^2$

$1.43 * r^2$

1.43 * (5.6)^2

1.43 * 31.36

44.8cm^2.



Therefore the Area of sector = 44.8cm^2.

Answer 2

Hey,
Friend,

Hope this will help you...