Question

please answer fast my question
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Answer 1

Answer:

1) a ÷ b = -1

=> a/b = -1

=> a = -b (Multiply both side with b)

Therefore the pair is (a,-b) Therefore when a is 2 then b is -2

And b ≠ 0.

=>(1,-1),(2,-2),(3,-3)..............

2) a ÷ b = -9

=> a/b = -9

=> a = -9b ( Multiply both side with b)

Therefore the pair is (a , -9b) Therefore when a = 0 then b is zero and when a = 1 then b is -1/9 which is not an integer Therefore a must be in multiple of 9 to get b as an integer

And b ≠ 0.

=>(9,-1),(18,-2),(27,-3)..............

3) a÷b = 0

=> a/b = 0

=> a = 0 ( Multiply both side with b)

Therefore the order pair is (0,b)

Here a must be equal to zero and b must not equal to zero

=>(0,7262),(0,726),(0,-26).............

4) a÷b = -2

=> a/b = -2

=> a = -2b ( Multiply both side with b)

b ( Multiply both side with b)Therefore the pair is (a , -2b) Therefore when a = 0 then b is zero and when a = 1 then b is -1/2 which is not an integer. Therefore a must be in multiple of 2 to get b as an integer

And b ≠ 0.

=> (2,-1),(4,-2),(6,-3).............