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1) in triangle ABC
By Pythagoras theorem
h²=b² +p²
h² = 8²+6²
= 64+36
=√100
=10²
ac = 10 cm
so,
as BN is a perpendicular on Ac so an is half of ac = 5 cm
if
here by Pythagoras theorem
6² = 5²+an²
36 =25 +an
an = 36-25
= 11
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