PLEASE ANSWER FAST!!
On a morning walk, three boys step off together and their steps measure 45 cm, 40 cm and 42 cm respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps.
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Answered by
1
here it is evident that we find LCM of 45,40,42
hence they should travel
hence they should travel
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siddhartharao77:
The question is to calculate distance. So the answer should be in km.
distance can also be in cm
still if you want then convert
ohhh...k
ok i will convert..Thanks for response
Answered by
3
Prime factorization of 45 = 3 * 3 * 5
Prime factorization of 40 = 2 * 2 * 2 * 5
Prime factorization of 42 = 2 * 3 * 7
LCM(45,40,42) = 2 * 2 * 2 * 3 * 3 * 5 * 7
= 2520.
Therefore the minimum distance each should walk = 2520cm
= 0.0252km
= 25.2m.
Hope this helps!
Prime factorization of 40 = 2 * 2 * 2 * 5
Prime factorization of 42 = 2 * 3 * 7
LCM(45,40,42) = 2 * 2 * 2 * 3 * 3 * 5 * 7
= 2520.
Therefore the minimum distance each should walk = 2520cm
= 0.0252km
= 25.2m.
Hope this helps!
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