Question

please answer fast please​

Answer 1

Step-by-step explanation:

Given:-

The zeroes are 2 and -1/3

To find:-

Find the Quadratic Polynomial if it's zeroes are 2 and -1/3?

Solution:-

Given zeroes are 2 and -1/3

Let α = 2 and β = -1/3

We know that

If α and β are the zeores then the quardratic polynomial is K[x^2-(α+β)x+αβ]

On Substituting these values in the above formula then

=> K[x^2-(2+(-1/3))x+(2)(-1/3)]

=>K[x^2-{(6-1)/3}x+(-2/3)]

=>K[x^2-(5/3)x+(-2/3)]

=>K[(3x^2-5x-2)/3]

If K = 3 then the Polynomial is

=> 3[3x^2-5x-2)/3]

On cancelling 3 then we get

=> 3x^2-5x-2

The Polynomial = 3x^2-5x-2

Answer:-

The required Polynomial whose zeroes are 2 amd -1/3 is 3x^2-5x-2

Used formulae:-

• If α and β are the zeores then the quardratic polynomial is K[x^2-(α+β)x+αβ]

Answer 2

Answer:

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