Question

please answer fast please​

Answer 1

Step-by-step explanation:

Given:-

A ={ x:x set of even prime }

B ={x:x is a natural number <12}

C = {x:x is a multiple of 4 less than or equal to 12}

D ={x:x is a factors of 12}

To find:-

Find the following:

I)AUB

2)BnC

3)C-D

4)A-D

Solution:-

Given that

A ={ x:x set of even prime }

A = {2}

B ={x:x is a natural number <12}

B = {1,2,3,4,5,6,7,8,9,10,11}

C = {x:x is a multiple of 4 less than or equal to 12}

C ={4,8,12}

D ={x:x is a factors of 12}

D ={1,2,3,4,6,12}

now,

1)AUB:-

=> {2} U {1,2,3,4,5,6,7,8,9,10,11}

=>{1,2,3,4,5,6,7,8,9,10,11}

AUB = B={1,2,3,4,5,6,7,8,9,10,11}

2)BnC:-

=> {1,2,3,4,5,6,7,8,9,10,11} n{4,8,12}

=> {4,8}

BnC ={4,8}

3)C-D:-

=> {4,8,12} - {1,2,3,4,6,12}

=> {8}

C-D = {8}

4)A-D:-

=> {2} - {1,2,3,4,6,12}

=>{ }

A-D = { }

Answer:-

1) AUB = B={1,2,3,4,5,6,7,8,9,10,11}

2)BnC ={4,8}

3)C-D = {8}

4)A-D = { }

Answer 2

Answer:

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