Question

please answer fast please​

Answer 1

Step-by-step explanation:

Solution:-

See the above attachment

Given Polynomial P(x) = x^2-x-12

To get the zeores we write P(x) = 0

=> x^2-x-12 = 0

=>x^2-4x+3x-12 = 0

=>x(x-4)+3(x-4)=0

=>(x-4)(x+3) = 0

=>x-4 = 0 or x+3 = 0

=>x = 4 or x =-3

The zeroes are 4 and -3

Graph of x^2-x-12:-

points:

The points are (0,-12),(1,-12),(2,-10),(3,-6),(4,0),(-1,-10),(-2,-6),(-3,0)

Scale :-

Taking on x-axis 1 cm = 1 unit

On y-axis 1 cm = 2 units

Observation:-

The graph of the given Polynomial is a u-shaped curve is called Parabola.

The graph cuts the x-axis at (4,0) and (-3,0)

Result:-

The zeroes are 4 and -3

Answer 2

Step-by-step explanation:

my 94865 7256 send your id