Question

please answer fast? please answer?​

Answer 1

➡Here is ur answer mate

14) Separating funnel

15) Distillation

16) Water

17) Alcohol and Water

18) I think it will be 6℅

19) 5℅

20) 20℅

I don't think so my answers are correct but I tried to answer...

Answer 2

Answer:

14. C) Separating funnel

15. D) Distillation

16. A) Water

17. A) Water & B) Alcohol

18. C) 4%

19. A) 5%

20. C) 20%

Explanation:

14. Two immiscible liquids, like oil and water, can be separated by using Separating Funnel. The mixture of oil and water forms two separate layers because they are completely insoluble in each other. Oil forms the upper layer while water forms lower.

15. Fractional distillation is used for the separation of a mixture of two or more miscible liquids for which the difference in boiling points is less than 25K. [Note : Fractional distillation for <40K or <40°C, Simple distillation for >40K or >40°C]

16. Aqueous means water

17.  In the tincture of iodine, the solvent is alcohol and water while the solute is iodine. Tincture of iodine is also known as a weak iodine solution or iodine tincture. Iodine tincture is an antiseptic used to disinfect the wounds.

18. We know that

$\boxed {\text {\bf{Mass\% = \dfrac{\text{Mass of solute}}{\text{Mass of solution}} \times 100 }}}$

Here , mass of solute = 5gm, mass of solvent = 120g

So, mass of solution= 120 + 5 = 125g

Mass % = $\frac{5}{125} \times 100$

$=> \frac{1}{25} \times 100\\\\=> \bf{\underline {\underline{4 \%}}}$

19. We know that,

$\boxed {\text {\bf{Mass by volume \% = \dfrac{\text{Mass of solute}}{\text{Volume of solution}} \times 100 }}}$

Here, mass of solute = 2.5g, Solution volume = 50ml

So,

${\text {{Mass by volume \% = \dfrac{\text{2.5}}{\text{50}} \times 100 }}}$

$=> \dfrac{250}{50} \\\\=> \underline {\underline{\mathbf{5 \%}}}$

20. We know that,

$\boxed {\text {\bf{Mass by mass\% = \dfrac{\text{Mass of solute}}{\text{Mass of solvent}} \times 100 }}}$

Here, mass of solute = 20g ; Mas of solvent = 100g

${\text {{Mass by mass \% = \dfrac{\text{20}}{\text{100}} \times 100 }}}\\\\=> \underline{\underline{\bf{20\%}}}$

$\Huge {\textsf{Hope it helps!!}}$

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