Question

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Answer 1

Answer:

Step-by-step explanation:

1) (-3,-2)

2) 1,-1

3) 45 degree

4) 2

5) both p,q are true

6) 2

Answer 2

Step-by-step explanation:

Solutions:-

1) Option C

The point (-3,-2) lies in Q3

Reason :-

Both coordinates are negative.

2)

Given Polynomial is x^2-1

To get the zeores we write it as

x^2-1 = 0

=>x^2-1^2 = 0

(x+1)(x-1) = 0

Since (a+b)(a-b)=a^2-b^2

=]x+1 = 0 or x-1 = 0

=> x = -1 or 1

The zeores are -1 and 1

Option B

3)False

Given Polynomial = 7x-5

To get the zeores we write it as

=>7x-5 = 0

=>7x = 5

=>x = 5/7

The zero = 5/7

4)

Given that

Tan θ = Cot θ

We know that

Cot θ = Tan (90°-θ)

=> Tan θ = Tan (90°-θ)

=> θ= 90°-θ

=>θ +θ = 90°

=> 2θ = 90°

=>θ = 90°/2

=>θ = 45°

The value of θ = 45°

5)

Given series is 2,4,6,8,10...

First term = 2

Common difference

t2-t1 = 4-2=2

t3-t2 = 6-4=2

t4-t3=8-6=2

t5-t4=10-8=2

Common difference = 2

Since the common difference is same throughout the series they are in the AP

6) option C

Both p and q are true

7) Option A

The graph of the given Polynomial cuts the x-axis at two different points so it has 2 zeroes