Question

please answer fast! ​plz

Answer 1

Answer:

Mass of 1st shell (M1) = 40kg

Initial Velocity of 1st shell (U1) = 72km/hr = 20m/s

Final velocity of 1st shell (V1) = 0

Mass of 2nd shell (M2) = 40-15=25kg

Initial Velocity of 2nd shell (U2) = 0

Final velocity of 2nd shell (V2) = ?

By Applying, Law of conservation of momentum

M1U1+M2U2=M1V1+M2V2

40×20+15×0 = 40×0+25×V2

800+0 = 40×0+25×V2

800 = 25V2

V2 = 32m/s.

So, the velocity of other piece is 32m/s.