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Question 4,5.........
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x = √(2a+1) + √(2a-1) / √2a+1 - √2a-1
x = (√(2a+1) + √(2a-1))^2 / (√2a+1 - √2a-1)(√(2a+1) + √(2a-1))
x = (2a + 1) + (2a-1) + 2√(2a+1)√(2a-1) / (2a+1) - (2a-1)
x = 4a + 2 √ (4a^2 - 1) / 2
2x = 4a + 2√(4a^2 - 1)
(x - 2a)^2 = 4a^2 - 1
x^2 + 4a^2 - 4ax = 4a^2 - 1
x^2 - 4ax + 1 = 0
x = (√(2a+1) + √(2a-1))^2 / (√2a+1 - √2a-1)(√(2a+1) + √(2a-1))
x = (2a + 1) + (2a-1) + 2√(2a+1)√(2a-1) / (2a+1) - (2a-1)
x = 4a + 2 √ (4a^2 - 1) / 2
2x = 4a + 2√(4a^2 - 1)
(x - 2a)^2 = 4a^2 - 1
x^2 + 4a^2 - 4ax = 4a^2 - 1
x^2 - 4ax + 1 = 0
AJAYMAHICH:
kuch bhi nhi krna bs equation ko solve krna h
you can do it
But how
By what formula
(a+b)(c+d). multiply krna aata h kya inhe ????
By arrow method??
hmm good
Ok thank you
and (a+b)^2 ka formula bhi janti hogi tum
Kkkk
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