Math, asked by garry7779, 1 year ago

Please answer fast.......
Question 4,5.........

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Answered by AJAYMAHICH

1

x = √(2a+1) + √(2a-1) / √2a+1 - √2a-1

x = (√(2a+1) + √(2a-1))^2 / (√2a+1 - √2a-1)(√(2a+1) + √(2a-1))

x = (2a + 1) + (2a-1) + 2√(2a+1)√(2a-1) / (2a+1) - (2a-1)

x = 4a + 2 √ (4a^2 - 1) / 2

2x = 4a + 2√(4a^2 - 1)

(x - 2a)^2 = 4a^2 - 1

x^2 + 4a^2 - 4ax = 4a^2 - 1

x^2 - 4ax + 1 = 0

AJAYMAHICH: kuch bhi nhi krna bs equation ko solve krna h

AJAYMAHICH: you can do it

garry7779: But how

garry7779: By what formula

AJAYMAHICH: (a+b)(c+d). multiply krna aata h kya inhe ????

garry7779: By arrow method??

AJAYMAHICH: hmm good

garry7779: Ok thank you

AJAYMAHICH: and (a+b)^2 ka formula bhi janti hogi tum

garry7779: Kkkk

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