please answer fast question 8
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let the equal angles be x
as we know, sum of all angles of quadrilaterals =360°
then,
angle A + B + C + D =360°
85°+75°+x+x = 360°
160°+2x = 360°
2x = 360°- 160°
2x = 200°
x = 100
Hope it helps you!!!!!
as we know, sum of all angles of quadrilaterals =360°
then,
angle A + B + C + D =360°
85°+75°+x+x = 360°
160°+2x = 360°
2x = 360°- 160°
2x = 200°
x = 100
Hope it helps you!!!!!
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