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range of y=|x-3|+|x-1|+|x-2|is
Answers
Answer:
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Step-by-step explanation:
Given , y=(x−2)(x−3)(x+1)=x3−4x2+x+6
Now ,
At x=0,y=6
At y=0,x=−1,2,3
So the graph of the given equation goes through the points (0,6)(−1,0),(2,0),(3,0).
So the points in the graph will be like this —
Now how do the points will connect to each other? To know this firstly we need to know if there are any pick points between the graph of the equation.
In Pick Point dydx=0
We got, y=x3−4x2+x+6
So , dydx=3x2−8x+1
As, dydx=0
So, 3x2−8x+1=0⇒x=4±13√3
Now if , x=4±13√3
Then, y=70±2613√27
So there are 2 Pick Points in this graph and they are at (4−13√3,70+2613√27) and (4+13√3,70−2613√27).
So the graph will be like this with these pick points —
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Step-by-step explanation:
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