Question

Please answer fast.......
Rationalise the denominators of the following
√3 / 2√7 - 2√3​

Answer 1

$= > \: \: \frac{ \sqrt{3} }{2 \sqrt{7} - 2 \sqrt{3} } \\ \\ = > \: \: \frac{ \sqrt{3} }{2 \sqrt{7} - 2 \sqrt{3} } \times \frac{2 \sqrt{7} + 2 \sqrt{3} }{2 \sqrt{7} + 2 \sqrt{3} } \\ \\ = > \: \: \frac{ \sqrt{3} (2 \sqrt{7} + 2 \sqrt{3}) }{ {(2 \sqrt{7}) }^{2} - {(2 \sqrt{3} )}^{2} } \\ \\ = > \: \: \frac{ \sqrt{3}(2 \sqrt{7} + 2 \sqrt{3} ) }{28 - 12} \\ \\ = > \: \: \frac{2 \sqrt{21} + 6}{16} \\ \\ = > \: \: \frac{ \cancel{2}( \sqrt{21} + 3) }{ \cancel{16}} \\ \\ = > \: \: \frac{ \sqrt{21} + 3 }{8}$