Math, asked by Anonymous, 8 months ago

Please answer fast Solve: x/a+y/b=a+b ; x/a2 + y/b2=0

Answers

Answered by divyjain16
0

X/a + y/b = a+b 

⇒y/b = a + b - x/a     .................. i 

x/a² + y/b² = 2 ................ii

⇒x/a² + y/b x1/b = 2

⇒x/a² + a+b/b - x/ab = 2                 puttting i 

⇒x(b-a)/a²b = (b-a)/b

⇒x = a²

so x = a² 

using ii we get 

y = b²

so x=a² and y=b² ANSWER
Answered by Anonymous
0

Answer:

x/a+y/b-(a+b) = 0……………..(1).

x/a^2+y/b^2–2 = 0…………………(2).

x/{-2/b+(a+b)/b^2} = y/{-(a+b)/a^2+2/a} = 1/{1/ab^2–1/a^2b}.

x/{(a-b)/b^2} = y/{(a-b)/a^2} = 1/{(a-b)/a^2.b^2}.

x.b^2 = y.a^2 = a^2.b^2.

x= a^2.b^2/b^2 =a^2. Answer.

y =a^2.b^2/a^2 = b^2. Answer.

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