Question

please answer fast..
spam=10 answers report..

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Answer 1

Answer:

$\dfrac{2tanx}{1+tan^2x}$

= $\dfrac{2\dfrac{sinx}{cosx}}{sec^2x}$

= $\dfrac{2\dfrac{sinx}{cosx}}{\dfrac{1}{cos^2x}}$

= $2\dfrac{sinx}{cosx} \times \dfrac{cos^2x}{1}$

= 2sin x cos x

= sin 2 x

L.H.S = R.H.S

Answer 2

Answer:

2tanx

1 + tan²x

sinx

COSX

sec²x

sinx 2

1 cos²x

sinx

2 COSX

=

=

X

cos²x

1

= 2sin x cos X

= sin 2 x

L.H.S R.H.S