Math, asked by piyushbd28, 2 months ago

PLEASE ANSWER FAST

The equation of the circle touching the y-axis at
the origin and passing through (b, c) is

(a) b (x^2 - y^2) = x (b^2 - c^2)
(b) b (x^2 - y^2) = x (b^2 + c^2)
(c) b (x^2 + y^2) = x (b^2+ c^2)
(d) b (x^2 + y^2) = x (b^2 - c^2)​

Answers

Answered by shravani29072006
0

Answer:

option no. c) n(x^2 +y^2) = x(b^2 ,+c^2) is correct option

Answered by sanx283
0

Step-by-step explanation:

option c is the right answer b (x^2 + y^2) = x (b^2+ c^2)

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