Question

please answer fast the nth term of an ap is given by an=3+4n the common difference is​

Answer 1

Answer:

a1 = 3+4×1

= 7

a2 = 3+4×2

= 3+8

= 11

common difference d = a2 - a1

= 11 - 7

= 4

Therefore, common difference is 4

Answer 2

$Given \: n^{th} \:term \: of \: an \:A.P :$

$\boxed{\pink{ a_{n} = 3 + 4n }}$

$i) If \: n = 1 \: \implies a_{1} = 3 + 4 \times 1$

$= 3 + 4$

$= 7$

$ii) If \: n = 2 \: \implies a_{2} = 3 + 4 \times 2$

$= 3 + 8$

$= 11$

$\red{Common \: difference (d)}$

$= a_{2} - a_{1}$

$= 11 - 7$

$= 4$

Therefore.,

$\red{Common \: difference (d)} \green { = 4}$

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