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The taxi fare in the city in such that rupees 50 is fixed amount and rupees 16 per kilometre is charged. Taking the distance covered as X km and total fare as rupees Y . Write the line or equation in X and Y . What is the total fare for 20 km?..
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Answers
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fixed cost =50
16×x=fare for the trip except fixed cost
thus required equation will be 50+16x=y
where y is the total fare
for 20 km, x=20
thus total fare=50+(16×20)=50+320=Rs.370
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0
Answer:
Equation formed: y = 50 + 16x
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