please answer fast!! There is arrow in the question
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Hi dea...!
Let first digit be 'X' then 5th digit is '3X'
Let 2nd digit be 'Y' then 3rd digit is 'Y-3' and 4th digit is 'Y+4'
then the number is '(X)(Y)(Y-3)(Y+4)(3X)'
From the above we can say 3X<=9 so X<=3 and any of the digit in the number is
<=9 and also given that 3 pairs sum is 11...
so make trial and error..
If X=1...any of the number is 10 which is wrong trial....
If X=2...then let Y+4=9 ==> Y=5 then number is 25296
First pair 2+9=11
Second pair 2+9=11
Third pair 5+6=11
Now the answer is 25296
Hope it helps u..!
#bipasha
Let first digit be 'X' then 5th digit is '3X'
Let 2nd digit be 'Y' then 3rd digit is 'Y-3' and 4th digit is 'Y+4'
then the number is '(X)(Y)(Y-3)(Y+4)(3X)'
From the above we can say 3X<=9 so X<=3 and any of the digit in the number is
<=9 and also given that 3 pairs sum is 11...
so make trial and error..
If X=1...any of the number is 10 which is wrong trial....
If X=2...then let Y+4=9 ==> Y=5 then number is 25296
First pair 2+9=11
Second pair 2+9=11
Third pair 5+6=11
Now the answer is 25296
Hope it helps u..!
#bipasha
The above one in the comment is the r8 answer
I not understand your explanation...
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so possible combinations are (2,9),(3,8),(4,7),(5,6)
that means 0 and 1 is not there.
let no is "abcde"
now given that,
d=b+4;
c=b-3;
hence d=c+7;
hence c must be 2
hence d=9;
hence b=5;
also a=3e is given
hence a=6 & e=2.
hence number is 65292