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(I) ∆ ABC is an isoceles triangle.
(ii) interior angles of ∆ ABC are :-
sum of all angles of a triangle is 180⁰.
angle ACB and angle ABC are equal because they are the base angles of equal sides of the triangle.
let angle ACB = x
=> angle A + angle ABC + angle ACB = 180⁰
=> 50⁰ + angle ABC + angle ACB = 180⁰
=> 50⁰ + x + x = 180⁰
=> 50⁰ + 2x = 180⁰
=> 2x = 180 - 50
=> 2x = 130
=> x = 130 ÷ 2
=> x = 65
so , all the angles of the triangle are 50⁰, 65⁰, 65⁰.
(iii) x + angle ABC = 180⁰ ( linear pair )
x + 65 = 180
x = 180 - 65
x = 115⁰
y + angle ACB = 180⁰ ( linear pair )
y + 65 = 180⁰
y = 180 - 65
y = 115⁰
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