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heya it's Aastha.......
◆let the speed of the train be X in time taken is Y.
according to question.
●1st condition .
(X + 10)(Y - 2 ) = xy ( distance= speed × time) .
x - 5y = -10.------1
●2nd condition.
(x-10)(y+3)=xy
3x -10y = 30.------2
◆by substitution method ....
from eq 1 .
x = -10+5y.
putting the value in eq. 2.
◆{y = 12 } &{ x = 50}.
thus,
the speed of train is 50 km per hour and the time is taken by train is 12 hour .
I hope it help you ✌️
◆let the speed of the train be X in time taken is Y.
according to question.
●1st condition .
(X + 10)(Y - 2 ) = xy ( distance= speed × time) .
x - 5y = -10.------1
●2nd condition.
(x-10)(y+3)=xy
3x -10y = 30.------2
◆by substitution method ....
from eq 1 .
x = -10+5y.
putting the value in eq. 2.
◆{y = 12 } &{ x = 50}.
thus,
the speed of train is 50 km per hour and the time is taken by train is 12 hour .
I hope it help you ✌️
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