Question

please answer fast tomorrow is my exam

Answer 1

divide 3 - √7 to numerator and denominator and go on simplifying the steps

Answer 2

$Given : \frac{3 + \sqrt{7} }{3 - \sqrt{7} }$

On rationalizing, we get

$\frac{(3 + \sqrt{7})(3 + \sqrt{7}) }{(3 - \sqrt{7})(3 + \sqrt{7} ) }$

$\frac{(3 + \sqrt{7})^2 }{3^2 - ( \sqrt{7})^2 }$

$\frac{9 + 7 + 6 \sqrt{7} }{9 - 7}$

$\frac{16 + 6 \sqrt{7} }{2}$

$8 + 3 \sqrt{7}$

It is in the form of $a + b \sqrt{7}$

Where a = 8, b = 3.


Therefore the value of a = 8 and b = 3.


Hope this helps!